1. The problem statement, all variables and given/known data A small ball is projected with a speed of 10 m/s at an angle of elevation of p from the top of a vertical pole whose height is 15 m from the level ground. The ball hits the ground at a point whose horizontal distance from the foot of the pole is 20 m . Find the value of p . gravity=10 m/s^2 2. Relevant equations 3. The attempt at a solution Consider horizontal motion , s=Vx t 20=10 (cos p) t t=2/(cos p) --1 Consider vertical motion, 15=10 (sin p)(2/(cos p))+1/2 (10)(2\(cos p))^2 15 cos^2 p -20 sin p cos p -20 =0 3 cos 2p - 4 sin 2p=1 5 cos (2p+53.13)=1 2p+53.13=78.46 therefore , p=12.67 degrees Am i correct ?