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Projectile motion

  • Thread starter mandy9008
  • Start date
127
1
1. Homework Statement
A fireman 52.0 m away from a burning building directs a stream of water from a ground-level fire hose at an angle of 34.0° above the horizontal. If the speed of the stream as it leaves the hose is 40.0 m/s, at what height will the stream of water strike the building?


2. Homework Equations
Voy=Vo sin θ
t= Voy / g
y= Voy t - 1/2 g t2


3. The Attempt at a Solution
Voy= 40.0 m/s sin 34.0
Voy= 22.37 m/s

t= 22.37 m/s / 9.8 m/s2
t= 2.28s

y= 22.37 m/s (2.28s) - 1/2 (9.8 m/s2)(2.28s)2
y= 25.53 m
1. Homework Statement



2. Homework Equations



3. The Attempt at a Solution
 
133
0
Your solution method is pretty much correct except for your calculation of the time. The equation you've used is [itex]t = v_{0y}/g[/itex], which is not valid. You can use [itex]t = x/v_x[/itex], however since the horizontal motion has no acceleration. That should do the trick.
 
127
1
22.7 m thanks!
 

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