1. The problem statement, all variables and given/known data Suppose we attempt to account for air resistance in our projectile motion in the following (incorrect) way: we alter g so that the acceleration in the y direction is -8 m/s2, and introduce a horizontal acceleration of -3 m/s2. With these changes, find the landing point of a projectile fired with initial speed 32 m/s at an angle of 25°. 2. Relevant equations x - x0 = (v0 cos theta0)t + 1/2 at2 (note this is changed from the textbook definition- by the addition of the term (+ 1/2 at2)- bc of the introduction of horizontal acceleration) y - y0 = (v0 sin theta0)t + 1/2 at2 vy = v0 sin theta0 + at vy2 = (v0 sin theta0)2 + 2a(y - y0) and other constant acceleration equations altered for the purposes of projectile motion for constant acceleration: R = (2v02/g) (sin 2theta0) where R = the horizontal range of the projectile 3. The attempt at a solution I was wondering if there was a way to solve this without assuming the landing point is the same as the launch point (constant elevation.) I solved it assuming constant elevation, but as it doesn't say that, I don't know if that was perhaps a bad assumption. With my assumption, I found that the projectile's landing point was 80.9 m from its starting point.