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Projectile motion

  1. Sep 23, 2010 #1
    1. The problem statement, all variables and given/known data

    A stone is projected vertically with a initial velocity u. Another stone projected from the same position verticaly with same velocity u after time t. Find the velocity of both stones when they meet together & time taken to meet.

    2. Relevant equations

    S = ut + 1/2 at2
    v = u + at
    V2 = u2 + 2as

    3. The attempt at a solution

    Max height = u/2g
    time taken reach max height = u/g
    Time taken to reach first stone ground = 2u/g

    So I took time taken to meet two as

    t + t/2 = 3t/2

    Instance velocity of bath should be equal when they meet.
    So
    Using v = u + at
    V= u + 3gt/2

    But answer is given as gt/2, I cannot reach to this

    & time is given as t/2 + u/g

    I can take time if the t is time taken to reach the max point.
    t= u/g
    Then
    Time = t/2 + u/g

    Please help me to reach to this answer.
    :uhh:
     
    Last edited: Sep 23, 2010
  2. jcsd
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