hey, pls smne take a look at this question, i need help. " A man stands on a cliff 15m above the ground and throws a little rock off the cliff with a velocity of 30m/s at an angle of 33.0degrees. Air resistance can b neglected. what is the speed of the rock just before it hits the ground?" i guessed the equation i'd use to solve this would be " v= u^2 + 2gh " but then, what would b the intial velocity? the height would b the height of the cliff + the height above the cliff, right? then since at that point , the rock is at maximum height, would the velocity at that point be 0 ? thanks!!!