Hi, i have a small problem, can you guys help?
A man jumps a maximum horizontal distance of 3 meters. How far can he jump on the moon, where downward acceleration is g/6?
A 2 meter tall basketball player, 10 meters away from the hoop 3.05 meters high, launches a basketball at a 45 degree angle. What initial velocity must he use to get it in the hoop without touching the rim?
Vx= vintial*(cos theta)
V-y final= V-initial (sin theta) + AT
X displacement= V * T
The Attempt at a Solution
For number one-
I split it in half- so now I'm trying to solve
A ball is rolled off the edge of a table and lands 1.5 meters away at 45 degrees. What is Vx,
Vy final, T, and height of the table?
So first, I use
Height= 1/2 g t^2
H= 4.9 *t^2
Since D= Vx * T,
Then T= D/vx
So H= 4.9 * D^2/vx^2
Tan 45= Vy/Vx,
D= 1.5 meters
So H= 4.9 * 2.25/ (vy/tan45)
H= 4.9* 2.25/vy^2
and this is where i stop.
For the second question, I was thinking of perhaps the changing it to
A ball is thrown from ground level, at a 45 degree angle, to a hoop 1.05 degrees.
After that, I have no clue
Thanks for answers!