Finding Maximum Altitude of a Rocket

In summary, the rocket reaches a height of 59.603 kilometers afterburnout from its distance traveled of 105.16 kilometers.
  • #36
okay~thank you very much. now the next question is the time of flight from launching to impact...answer is 308.65s
i don't know what the question talking about?
what is the impact it means?
 
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  • #37
stupif said:
okay~thank you very much. now the next question is the time of flight from launching to impact...answer is 308.65s
i don't know what the question talking about?
what is the impact it means?

Presumably that would be when the rocket crash-lands on the ground. After the fuel was used up the rocket became a free-falling projectile. It will rise to its maximum height and then fall back to the ground.
 
  • #38
thanks, i got it, now the next question is the distance from launched pad to impact point.
the answer is 139km

1st i find the distance at s1, 20700cos 70 = 7029.82m
2nd, i find the distance between s1 and s2 , s=vt, s= 1380cos70 X 28.19s = 13305m
3rd, i find the distance between s2 to the ground, s=vt , s= 1380cos70 X 146.50s =69146m

total up is 89480.82m

i think something wrong in step 2 and 3.
 
  • #39
It's difficult to comment without knowing where the numbers and constants are coming from. What are s1 and s2? Where do the time intervals 28.19s and 146.50s come from?
 
  • #40
s1 is the distance from rest to h1
s2 is the distance from h1 to h2 when the engines shut off

mistake for 28.19. it should 30s
146.50 is come from this equation, s = ut +1/2at^2 , 105.16km= 0t+ 1/2(9.8)t^2
t= 146. 50s
 
  • #41
stupif said:
s1 is the distance from rest to h1
s2 is the distance from h1 to h2 when the engines shut off

mistake for 28.19. it should 30s
146.50 is come from this equation, s = ut +1/2at^2 , 105.16km= 0t+ 1/2(9.8)t^2
t= 146. 50s

It looks as though your s1 and s2 values are horizontal distances, with s1 being the the horizontal distance from launch to where the fuel runs out, and s2 the horizontal distance from there to the maximum height.

Why do you take the time between s1 and s2 to be 30 seconds?
 
  • #42
sorry...mistake again...i know how to do already, just now made some mistakes in calculation.
thank you very much...
 

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