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Projectile motion

  1. Aug 6, 2017 #1
    1. The problem statement, all variables and given/known data
    2 projectiles are fired simultaneously from ground level with same initial speed (u).Both cover same horizontal distance of 160m on reaching the ground level .One of them reaches 6 sec prior to the other.Only gravitational acceleration g=10m/s squared governs the motion of both the projectile.Calculate u.


    2. Relevant equations
    Range(horizontal distance)=u squared sin 2×theta/g= Ux cos theta ×time
    Time=2u sin theta/g
    Where ,
    U is initial velocity
    Theta is the angle of projection
    and T is the time taken by the projectile to reach ground level.
    Note:vector u has 2 components which are Ux=u cos theta and Uy=u sin theta

    3. The attempt at a solution
     
  2. jcsd
  3. Aug 6, 2017 #2

    haruspex

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    An attempt is required. Forum rules.
     
  4. Aug 7, 2017 #3
    THE ATTEMPT AT A SOLUTION:
    I took the angle of projection of 1st projectile as theta and the angle of the 2nd one as 90 - theta (as there can be two angles of projection for the same range).
    I equated the range and the time ,that is
    T=t+6.As I have really limited knowledge of trigonometry, the resulting equation which I arrived at couldn't be solved by me.
     
  5. Aug 7, 2017 #4

    haruspex

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    Please post the equation. It might save time to post your working too, in case you have a mistake somewhere.
     
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