I did an experiment which involved a few trials. Here are the results:(adsbygoogle = window.adsbygoogle || []).push({});

distance rolled on table: 100 cm (all three trials).

height of table: 86.4 cm

time on table: 1.1 s (trial 1), 1.2 s (trial 2), 1.3 s (trial 3).

horizontal distance traveled in air: 36.1 cm (trial 1), 34.8 cm (trial 2), 34.8 cm (trial 3).

Ok so (1) What is the velocity the ball rolled with on the table? So [tex] v = \frac{d}{t} [/tex]. I got 91 cm/s (trial 1), 83 cm/s (trial 2), 83 cm/s (trial 3).

(2) The vertical component of the balls velocity when it leaves the edge of the table would be 0. Is this correct?

(3) Calculate the time that it takes the ball to reach the floor once it has left the table. Ok so I would use [tex] d = v_{y}_{0}t + \frac{1}{2}gt^{2} [/tex]. [tex] v_{y}_{0} = 0, d = 86.4 cm [/tex]. Are these the correct values for the variables?

(4) Find the horizontal distance that the ball should travel from the time it left the table until it hit the floor for the three trials. So would I use [tex] x = x_{0} +v_{x}_{0}t + \frac{1}{2}a_{x}t^{2} [/tex]? So would I use the 91 cm/s, 83 m/s, and 83 m/s, for the velocities, and 0.42 seconds for the time?

Thanks

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# Homework Help: Projectile Motion

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