1. The problem statement, all variables and given/known data A cannonball is launched with initial velocity of magnitude v0 over a horizontal surface. At what minimum angle θmin above the horizontal should the cannonball be launched so that it rises to a height H which is larger than the horizontal distance R that it will travel when it returns to the ground? (A) θmin = 76◦ (B) θmin = 72◦ (C) θmin = 60◦ (D) θmin = 45◦ (E) There is no such angle, as R > H for all range problems. 2. Relevant equations d = (vi+vf)/2)*t 3. The attempt at a solution H = (1/2)(v0sinθ)(t) and R = (v0cosθ)(t) Thus, if H = R, then (1/2)(v0sinθ)(t) = (v0cosθ)(t) =>tanθ = 2, so θ = 63.4°. I'm probably making a really obvious mistake here, but I'm not seeing it. Any help would be appreciated.