A projectile launched vertically from the surface of the Moon rises to an altitude of 370 km. What was the projectiles initial speed?
Vf ^2 = Vi^2 + 2ad
The Attempt at a Solution
distance = 370km x 1000 = 3.7E 5 meters
solving for Vi = sqroot of Vf^2 - 2ad
sqrt of 0 - -1.63 x 3.7E5 = 777m/s