Do you know a formula involving the gravitational constant G?y90x said:
haruspex said:
Not quite. If you have a force on the left then you need two masses on the right. Or you can have an acceleration on the left and just the attracting mass on the right.y90x said:
haruspex said:
You only need to know the vertical acceleration of the rock. According to the formula above, the force is proportional to its mass, so the acceleration is independent of its mass.y90x said:
haruspex said:
Let the mass of the rock be m. What is the gravitational force on it?y90x said:
haruspex said:
Use the formula you quoted in post #3. The unknown mass of the rock, m, appears in the answer.y90x said:
haruspex said:
No, the mass you are given is the mass of the planet.y90x said:
0.65 what? m/s2?y90x said:
Looks right.y90x said:
The gravity on Pluto is significantly weaker than on Earth, about 1/15th of Earth's gravity. This means that projectiles on Pluto will travel much farther and slower compared to on Earth.
The factors that affect a projectile's trajectory on Pluto are the initial velocity, the angle of launch, and the gravitational pull of Pluto. Additionally, air resistance is negligible on Pluto, so it does not play a significant role in the motion of projectiles.
When launched from the surface of Pluto, a projectile will follow a parabolic trajectory due to the gravitational pull of Pluto. However, due to the weak gravity, the projectile will travel much farther and slower compared to on Earth.
The trajectory of a projectile on Pluto would differ from that on Earth in many ways. Firstly, the projectile would travel much slower and farther due to the weaker gravity. Additionally, there is no air resistance on Pluto, so the projectile would not experience any drag force. The curvature of the projectile's path would also be less pronounced due to the weaker gravity.
Yes, a projectile can achieve escape velocity on Pluto. The escape velocity on Pluto is about 1.2 km/s, which is much lower compared to Earth's escape velocity of 11.2 km/s. This means that a projectile would require less initial velocity to escape the gravitational pull of Pluto.
