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Projectile Problem

  1. Sep 9, 2005 #1
    Suppose you throw a stone straight up with an initial velocity of 10.5 m/s and, 1.0 s later you throw a second stone straight up with the same initial velocity. The first stone going down will meet the second stone going up. At what height above the point of release do the two stones meet?
     
  2. jcsd
  3. Sep 9, 2005 #2
    What have you tried? Where are you stuck?

    You need to know the kinematics equations to answer this problem.

    HINT: The time for the second stone is (t-1)
     
  4. Sep 10, 2005 #3
    hm...basically i need help for the whole question
    i have no idea how to even start the question
     
  5. Sep 10, 2005 #4
    s(t)=-4.9t2+v0t+h

    Using this and the previous suggestion, you shouldn't have any trouble.
     
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