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Projectile Problem

  1. Sep 29, 2005 #1
    What am I doing wrong here? I am trying to arrive at a correct answer of 6.13m but can't get there...

    A falcon is moving horizontally at it's top speed (200 mi/h) at a height of 100m off the ground when it brings its wings in and drops into a freefall. How far does the bird fall vertically while traveling horizontally a distance of 100m?

    I've converted the speed into 89.4 m/s (from 200 mi/h) and then isn't it simply a freefall problem for a duration of 100m? If someone could help me set it up so I can visualize it I would be appreciative. I guess I've got the initial x and y displacement relative to the earth as well as the initial velocity, but now what?

    Thanks in advance!
     
  2. jcsd
  3. Sep 29, 2005 #2

    mukundpa

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    find time taken for 100m horizontal, with constant velocity. What vertical distance it falls in that time? (0.5gt^2)
     
  4. Sep 29, 2005 #3
    So would the constant velocity for that 100m segment simply be gravity or the x-component of the velocity (top speed)? I would guess that if you separate the components it would simply be freefall at gravity for 100m?

    Thanks for your help...
     
  5. Sep 29, 2005 #4
    the horisontal distance = Cos(angle)*V initial* time travelled.

    angle is zeor so cos 0 = 1 so you have 100 = 89.4*t and you solve for time.

    the vertical distance = Sin(angle)*V initial*t + 1/2 g*t^2

    Sin of 0 degrees cancels the speed, so vertical fall would be -4.9m/s^2 * t^2 that you found in the first equation.

    that's how i see it...but i only took phisics one in my junior year highschool. i don't know the numeric outcome...give it a quick try.

    edit: hold on i'll run the numbers for you.

    t of fall is 1.12 seconds (correctly sig figured assuming the 100 has 3 sig figs.

    -4.9*1.12^2= -6.15 if correctly sig figured or +6.15 if you're analizing a fall...

    you get it...im insulting your intelligence here with the positive/negative thing.

    my answer is slightly larger than the book's...by 2 centimeters becasue of repeated roundups due to sig figs rule. if i were to work with the 14 decimals i'd probably get 6.13
     
    Last edited: Sep 29, 2005
  6. Sep 29, 2005 #5
    OK, I'll take a look at it. Thanks for pondering it... I really appreciate it!
     
  7. Sep 29, 2005 #6
    Think the bird falls for 1.12 seconds?
     
  8. Sep 29, 2005 #7
    Ahh yes, you stated that in your response... THANKS! Now I know you're right - and I'm on the right track!
     
  9. Sep 29, 2005 #8
    yea. what i did not write is how i came up with this i mean thinknig process.

    well the bird is moving horisontally and suddenly starts to move vertically as well. horisontal speed won't change...and we only care about how far it falls during the time that it moves horisontally that distance. so the time of fall is the smae as the time it needs to travel that distance.

    that's why the time is 1.12 in one equation and can be plugged into second. sorry for confusion...
     
  10. Sep 29, 2005 #9
    Nah, makes perfect sense to me now. It's just a simple projectile - like a bullet fired from a gun with a dropped object - disregarding curvature of the earth, both would hit simultaneously because same y component. I think the time factor with this problem threw me off... thanks for explaining it...
     
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