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**1. Homework Statement**

Hi, I am just wondering if someone can check if this is the correct answer for this question. Thanks in advance

1 . A projectile is launched with a speed of 48m/s at an angle of 34 degrees BELOW the horizontal. Calculate the speed an direction of the projectile 2.5 seconds after launch. Ignore friction.

**2. Homework Equations**

x/y component . addition of vectors. v=vo+at

**3. The Attempt at a Solution**

This is my answer : 40 m/s at 3.3 degress South of East

I find it surprising that the final velocity of the projectile is less then the initial (which is 48m/s).

Here it is:

48 sin 34 = -26.8m/s

48 cos 34 = 39.8

v = vo +at

v = -26.8 + (9.8)(2.5) <--- + acceleration because motion is towards center of Earth

v = -2.3

From here I used addition of vectors in x/y component

x = 39.8

y = -2.2

After 2.5 seconds

Answer: vf = 40 m/s at an angle of 3.3 degrees <---- tan theta

Shouldn't the vf of the projectile (after 2.5 seconds) be greater then the vo? Since it has a + 9.8 m/s ^ 2 .

Thank you