- #1
jonniechung
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Homework Statement
Hi, I am just wondering if someone can check if this is the correct answer for this question. Thanks in advance
1 . A projectile is launched with a speed of 48m/s at an angle of 34 degrees BELOW the horizontal. Calculate the speed an direction of the projectile 2.5 seconds after launch. Ignore friction.
Homework Equations
x/y component . addition of vectors. v=vo+at
The Attempt at a Solution
This is my answer : 40 m/s at 3.3 degress South of East
I find it surprising that the final velocity of the projectile is less then the initial (which is 48m/s).
Here it is:
48 sin 34 = -26.8m/s
48 cos 34 = 39.8
v = vo +at
v = -26.8 + (9.8)(2.5) <--- + acceleration because motion is towards center of Earth
v = -2.3
From here I used addition of vectors in x/y component
x = 39.8
y = -2.2
After 2.5 seconds
Answer: vf = 40 m/s at an angle of 3.3 degrees <---- tan theta
Shouldn't the vf of the projectile (after 2.5 seconds) be greater then the vo? Since it has a + 9.8 m/s ^ 2 .
Thank you