1. The problem statement, all variables and given/known data An Archer is planning show an arrow at a target 125 meters aways in which the center is 2 meters above the ground. The arrow leaves his bow with a speed of 50m/s at an angle of 15 degrees and a height of 1 meter off the ground. a)How close does he come to hitting the center of the target. i.e. at what height does it impact the target? b) how long was the arrow in the air? c) With what velocity (magnitude and direction) does the arrow hit the target. 2. Relevant equations V = Vi + at change of x = Vit + 1/2(at^2) V^2 = Vi^2 + 2a(change of x) with component factor 3. The attempt at a solution I found the correct answer of b which is 2.65 seconds and I use it for the second equation to solve for Y final. I got 1.526m for Y final but my instructor said the answer is not correct. Where did I made a mistake and what is the correct way to solve for this problem.