(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An arrow fired horizontally at 41m/s travels 23m horizontally before it hits the ground. From what height was it fired?

2. Relevant equations

constant acceleration formula

3. The attempt at a solution

This is what i have done, however it is incorrect and the height of y is 1.54m(book's answers)

So to find y i had to find the time.

So...

x=23m

v-final(x)=41m/s

t=?

v-initial(x)=0m/s

using the constant acceleration formula:

[tex]x= \frac{v-initial - v-final}{2} * t[/tex]

[tex]23 = \frac{41}{2}t[/tex]

[tex]t= \frac{23}{20.5}[/tex]

t=1.12s

Now to find y

v-initial(y)=0m/s

a=-9.80m/s2

t=1.12s

y=?

i used y=v-initial*t + 0.5*a*t

eventually i get 6.15m

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