Projectile Question (1 Viewer)

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Separate the velocity vector into its two components.

[tex]{V_{x0}}={V_0}\cos{\theta}}[/tex]
[tex]{V_{y0}}={V_0}\sin{\theta}}[/tex]

You can then solve for the total time it will take to hit the ground by working with the y-component, and thus use the x-component to solve for the x displacement.
 
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84
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lets say i want to to the v(x)
id get
v(x) = 5 cos ?
i dont know the degree, usually i have 5 cos 60 degrees, then id have a V(x), this time id ont
 

Päällikkö

Homework Helper
517
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As it's fired horizontally, what's the angle?
 
786
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Use one of your kinematic equations.... how about [tex]V_{yf}^2=V_{y0}^2+2gd[/tex]. All of those variables, and gravity, are given to you. What can you solve for now?
 
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Päällikkö said:
As it's fired horizontally, what's the angle?
180 degrees right, tried that and i got real close, just a 0.01 away, think i got it
thx
 
84
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can i use 180 degrees?
 

Päällikkö

Homework Helper
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I'd use 0 degrees. With 180 you have to hassle with directions (you get negative cosine).
 

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