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Projectile Range Question

  1. Feb 7, 2010 #1
    1. The problem statement, all variables and given/known data
    A projectile's horizontal range on level ground is R =v0^2 sin2(theta)/g. At what launch angle or angles will the projectile land at half of its maximum possible range.

    3. The attempt at a solution

    So what i did was:
    Half the range occurs when sin(2θ) = 0.5

    So 2θ = arcsin(0.5)...so θ = 0.5*arcsin(0.5) = 15 (degrees)

    but when i enter that in it says there is more than one answer, how do i get the other answer?
  2. jcsd
  3. Feb 7, 2010 #2


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    Homework Helper

    If sin (alpha)=0.5, alpha can be 30 or 180-30 degrees.

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