# Homework Help: Projectile-STUMPED Once again.

1. Jun 13, 2007

1. The problem statement, all variables and given/known data

A diver springs upward from a board that is three meters above the water. At the instant she contacts the water her speed is 9.10 m/s and her body makes an angle of 75.0° with respect to the horizontal surface of the water. Determine her initial velocity, both magnitude and direction.

2. Relevant equations

Kinematics equations :)

3. The attempt at a solution

I already got 4.9 m/s as the magnitude of the vector, but can't seem to get the direction in degrees!

2. Jun 13, 2007

### Staff: Mentor

What's the horizontal component of her velocity?

3. Jun 13, 2007

i just used the (9.1)squared=v initial squared +2(-9.8)(-3) and got the v initial magnitude...i dont know how to get the components is why i'm confused actually

4. Jun 13, 2007

### Staff: Mentor

Hint: You have her final speed and angle. Use it!

5. Jun 13, 2007

ok, so i got 3.85 as vx and for vy =8.79 but how does that help me?

6. Jun 13, 2007

### Staff: Mentor

Show how you got that value.

Does the horizontal component of velocity change as the diver falls?

7. Jun 13, 2007