1. The problem statement, all variables and given/known data A projectile is thrown from the horizontal ground with a speed of 40 m/sec at an angle with the horizontal of 30 degrees. At what height will the projectile strike a high barrier located at a distance of 85m from the firing point? 2. Relevant equations ok so: point A is located at the point in which the projectile is launched point B is located at the point at which the projectile strikes the barrier point is located at the bottom of the barrier, on the ground directly below the striking point theta = 30 degrees change in time from A to B= [VB - VA] / acceleration dAB = distance from A to C * cos(theta) dBCx = VB (change in time from B to C) + 0.5a*(change in time B to C)2 3. The attempt at a solution change in time A to B = [0 - 40] / 9.8 = 4.08 sec dAB = 85m * cos(30) = 22m dBCx = 0 (4.08 sec) + 0.5 (9.8) (4.08)2 = 245 m ^my teacher said that this wasn't right. i think i went wrong on the acceleration-i don't think i am calculating it right or using the right value.