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An arrow is fired from the ground at the same instant a target is dropped off a 28.5m cliff. The arrow firing device is 20m from the base of the cliff. For any initial velocity of the arrow, the angle it is fired at remains constant (at about 54.9 degrees) in order to hit the target. Why does the angle remain constant?

I have proved this mathematically but this part of the problem requires a worded answer. I have thought it is perhaps because gravity acts equally upon the arrow and the target? But I feel this alone is not enough...

Thanks for the help.

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# Projectile with fixed angle

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