1. The problem statement, all variables and given/known data A baseball player leads off the game and hits a long ball to right field. The ball leaves the bat at an angle of 30.0o from the horizontal with a horizontal velocity of 40.0 m/s. How far will it travel in the air? 2) person throws bottle straight up in the air at velocity of 15m/s . How high is the bottle after 2 secs 2. Relevant equations Vy=Vyi +gt Vy=Vyit +1/2gt^2 3. The attempt at a solution I found the time in total to be 4.08. However this is asking time IN the air. Isn't that different from finding Vxi and multiplying by time ? How do I find it? 2)can I use by y=15m/s* 2+1/2* 9.8m/s^2 * 2 Is that correct?