I have a problem. So far, I have decided that this problem is using the Range Equation. Here it is - The initial speed of a cannon ball is 200m/s. If it is fired at a target that is at a horizontal distance of 2 km from the cannon, find A) the two projected angels that will result in the hit and B) the total time of flight for each of the two trajectories. Okay, now here is what I have so far------ R=(Vi^2sin2theta)/g R= 2km Vi= 200m/s Assuming a= 9.8m/s^2 take the eq from above and plug in the numbers and get 2km=(200m/s)^2*(sin2theta)/9.8m/s^2 solving for sin (2km) *(9.8m/s^2)/200m/s = sin2theta Am I correct? Please advise. If there is a better approach to this problem, please share.