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Okay, now here is what I have so far------

R=(Vi^2sin2theta)/g

R= 2km

Vi= 200m/s

Assuming a= 9.8m/s^2

take the eq from above and plug in the numbers and get

2km=(200m/s)^2*(sin2theta)/9.8m/s^2

solving for sin

(2km) *(9.8m/s^2)/200m/s = sin2theta

Am I correct? Please advise. If there is a better approach to this problem, please share.