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Projection Motion Question

  1. Mar 29, 2006 #1
    I am having a difficult time with the motion eqation when the problem only includes an X value and an angle. The problem is to fin the velease speed of the ball when a player makes a shot to a basket when he is 6.02 m from the basket and the basket is 2.05 m above the floor. The player is 2.05 m tall and the launch angle is 25 degrees.

    Attached is the method I used to do the calculation. I feel like I left something out.

    Attached Files:

  2. jcsd
  3. Mar 29, 2006 #2
    I can't see your work yet, but I got v0 = 8.78 m/s. Hope it helps. I'll check back later.

  4. Mar 29, 2006 #3
    V0=8.78m/s is right if we take g=9.8m/s^2.

    by using
    x=V0 cos(theta) t
    y=V0 sin(theta) t - 1/2 g t^2

    solving these two equations, you'll get the answer! remember y=0 m
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