Show that the curve is symmetrical about the x axis (without drawing the graph)
eq of the curve is : x^2 + 4y^2 = 1
also show that the curve is symmetric about the y axis
The Attempt at a Solution
To prove that the curve was symmetric abou the x axis, i made x the subject of the equation of the curve:
x=(1-4y^2)^0.5 (can be positive or negative)
Then i used simple intuition:
let a particular value of y be "k" and the corresponding value of x be "c".
by simple calculation, we can conclude that for y=-k , x will still be equal to "c"
Can anyone guide me if this proof is enough or it lacks something, for the latter case, please provide an alternative but suitable proof.