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Proof: Area of a polar equation

  1. Feb 16, 2005 #1
    Why is the area enclosed by a polar curve equal to [tex]\int \frac{1}{2}R^2 d\theta[/tex]

    What's the Riemann sum from which this is derived?
     
  2. jcsd
  3. Feb 16, 2005 #2

    Hurkyl

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    Divide the region into triangles emanating from the origin.
     
  4. Feb 16, 2005 #3
    That had been my original guess, thanks :)
     
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