Proof: Area of a polar equation

  • Thread starter DoubleMike
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  • #1
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Main Question or Discussion Point

Why is the area enclosed by a polar curve equal to [tex]\int \frac{1}{2}R^2 d\theta[/tex]

What's the Riemann sum from which this is derived?
 

Answers and Replies

  • #2
Hurkyl
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Divide the region into triangles emanating from the origin.
 
  • #3
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That had been my original guess, thanks :)
 

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