Proving by Induction: Product Rule for Derivatives with Multiple Functions

In summary, the problem asks to prove the formula \frac{d}{dx} \prod_{i=1}^k f_i (x) = (\sum_{i=1}^k \frac{ \frac{d}{dx} f_i (x)}{f_i (x)} ) \prod_{i=1}^k f_i (x) using induction on k. The product rule \frac{d}{dx} (uv) = u \frac{dv}{dx} + v \frac{du}{dx} is used in the solution. The proof involves assuming the formula is true for k, then proving it for k+1 by applying the product rule and matching the two sides. The
  • #1
Ed Aboud
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0

Homework Statement



Prove by induction on k that for all integers
[tex] \frac{d}{dx} \prod_{i=1}^k f_i (x) = (\sum_{i=1}^k \frac{ \frac{d}{dx} f_i (x)}{f_i (x)} ) \prod_{i=1}^k f_i (x) [/tex]

Homework Equations



Product rule
[tex] \frac{d}{dx} (uv) = u \frac{dv}{dx} + v \frac{du}{dx} [/tex]

The Attempt at a Solution



I am honestly not sure how to start this. It is the first one like this that I have tried.
 
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  • #2
This problem is harder to write than it is to solve. Let's write "'" for d/dx and call P(k) the product of the f_i and S(k) the sum of the f'_i/f_i. Then what you have above is (P(k))'=S(k)P(k). Assume that's true. Now you want to prove (P(k+1))'=S(k+1)P(k+1), correct? P(k+1)=P(k)*f_(k+1) and S(k+1)=S(k)+f'_(k+1)/f_(k+1), also ok? Apply the product rule to P(k)*f_(k+1) and see if you can match the two sides up. And don't forget to prove the n=1 case to start the induction.
 

1. How does induction work in proving the product rule for derivatives with multiple functions?

Induction is a mathematical proof technique that involves proving a statement for all natural numbers. In the case of the product rule for derivatives with multiple functions, induction allows us to prove the rule for any number of functions by first proving it for two functions, and then showing that if it holds for n functions, it also holds for n+1 functions.

2. Why do we need to use induction to prove the product rule?

The product rule for derivatives with multiple functions is a general rule that applies to any number of functions. Induction allows us to prove the rule for any number of functions by breaking it down into smaller cases and building upon each one. This is necessary because it would be impossible to prove the rule for an infinite number of functions individually.

3. Can you explain the steps involved in an induction proof for the product rule?

First, we prove the base case, which is usually the case for two functions. Then, we assume the statement holds for n functions and use this assumption to prove that it also holds for n+1 functions. This step is known as the inductive step. Finally, we conclude that the statement holds for all natural numbers by the principle of mathematical induction.

4. What is the significance of the product rule for derivatives with multiple functions in calculus?

The product rule is an important tool in calculus because it allows us to find the derivative of a product of two or more functions. This is useful in many applications, such as in optimization problems or in finding rates of change.

5. Are there any limitations to using induction to prove the product rule?

Induction can only be used to prove statements that hold for all natural numbers. Therefore, it may not be applicable to prove the product rule for derivatives with multiple functions if the functions involved are not defined for all natural numbers. Additionally, induction requires a strong base case and a clear inductive step, which may not always be easy to identify.

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