Prove that 3^n >= 2n+1 for all natural numbers.
3^n >= 2n+1 [is bigger or equal to]
The Attempt at a Solution
True for n=1
(2k+1)*3>=2k+3 <---can I just substitute 2k+1 into 3^k as per my assumption, because 3^k is bigger, and (2k+1)*3 is bigger than 2k+3? If so, is the proof complete?
Thanks in advance.