(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

2n-1

Sigma (3i+1) = n(6n-1)

i=0

prove for all positive n

2. Relevant equations

3. The attempt at a solution

It holds true for n=1

5=5

then P: m+1

2m+1

Sigma(3i+1) = (m+1)(6(m+1)-1) or 6m^2 + 11m + 5

i=0

then 2m+1

Sigma(3i+1) = m(6m-1) + (3(m+1)+1) + (3(m+2)+1) = 6m^2 + 5m + 11

i=0

I just cannot figure this out and it is driving me crazy. Please help clarify things. I even tried changing the first part to

2m

Ʃ(3(i-1)+1)

i=1

and still couldn't prove it.

Thanks for your time

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# Proof By induction Sigma notation...Please help

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