- #1

mathrocks

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Let m be a given positive integer with m>=2(So m remains constant throughout the problem) Let fn be the sequence of fibonacci numbers. Prove that for every integer n>=1, fm+n=(fm * fn+1) + (fm-1 * fn).

I'm not sure how I go about finding the base cases to start the proof. I know I'm suppose to set something equal to >=1 but I'm not sure what.