Prove algebraically that the sum of the squares of any two odd numbers leaves a remainder of 2 when divided by 4.
The Attempt at a Solution
not really sure what to do so excuse my bad attempt
where n is an integer:
(1^2 + 1^2)/4 = n + 2
thnx for ya help
as per rules, please only give one step away at a time and explain please :D thnx