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Homework Statement
Prove that:
[tex]2^n \geq n + 5[/tex] for all integer n > 5
Homework Equations
n/a
The Attempt at a Solution
This is what I did, just want to see if it's right.
Using mathematical induction:
Basis step:
When n = 3,
[tex]2^3 \geq 3 + 5[/tex]
Since 8 = 8, base case is proven
Inductive step:
Assume [tex]2^k \geq k + 5[/tex] for all integers k greater or equal to n.
We want to prove that [tex]2^{k+1} \geq k + 1 + 5[/tex]
Using our assumption, [tex]2^k \geq k + 5[/tex], I know that:
[tex]2(2^k) \geq 2(k + 5)[/tex]
=[tex]2^{k+1} \geq 2k + 10[/tex]
From here, if I can prove 2k+10 is greater or equal to k+6, then it will prove
[tex]2^{k+1} \geq k + 6[/tex]
So:
[tex]2k+10 \geq k + 6[/tex]
[tex] 2k \geq k - 4[/tex]
[tex] k \geq -4[/tex]
Thus is proven because k was said to be greater or equal to n which is at least 3. So the inequality is true.
Since inductive step is proven, [tex]2^3 \geq 3 + 5[/tex] must be true.
QED
Does this proof stand? I haven't had much practice with inequalities... so I'm very unsure about this proof.
Thanks.
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