Hi can anyone help me check if I've approached this question correctly and offer any help on part b) of the question? Thanks! a) Prove that if n is an integer and n^3 is a multiple of 2 then n is a multiple of 2. Let n^3 be a multiple of 2 but suppose n is not a multiple of 2. then n= 2k+1 => n^3 = (2k+1)^3 = (4k^3+4k+1)(2k+1) = 8k^3+12k^2+6k+1 = 2(4k^3+6k^2+3k)+1 = 2m + 1 where m = 4k^3+6k^2+3k ==> n^3 is not a multiple of 2 therefore by contradiction n^3 is a multiple of 2 and n must also be a multiple of 2. Is that correct? plz correct me if im wrong, im not too good at proof. b) Deduce that 3 (sqrt 2) is irrational.