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Proof involving Ampere's Law

  • #1

Homework Statement



Ampere's Law states [tex]
\int _C \vec{B} \cdot \vec{dr} = \mu_0 \ I
[/tex] .

By taking C to be a circle with radius r, show that the magnitude B = |B| of the magnetic field at a distance r from the center of the wire is [tex]
B = \frac{\mu_0}{2 \pi} \ \frac{I}{r}
[/tex]


The Attempt at a Solution



I really don't know where to start. I don't know what the components of B are, so I don't know how I'm supposed to compute this integral.
 
Last edited:

Answers and Replies

  • #2
834
1
What do you know about the B-field at a distace r from the wire, magnitude-wise? How can you use this knowledge in computing the integral?
 

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