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jdstokes

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Thanks.

James

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- Thread starter jdstokes
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- #1

jdstokes

- 523

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Thanks.

James

- #2

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Now, at each point on that sphere, observe that, by symmetry, the Electric Field must be radial and must have the same magnitude. In addition, the area elements [tex]d\vec A [/tex] are radially outward. Use these observations to sequentially simplify your integral.

Since r is arbitrary (as long as your sphere encloses the point charge that it is centered on), your expression works for arbitrary r.

(In a "proof" that involves the potential, you probably need to first prove that it exists. That is, show that the electric field is minus the gradient of a function for this situation. What condition must be imposed on the Electric Field?)

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