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I'm trying to understand how [itex]\frac{d}{dx} \mathrm{arccsc} x = -\frac{1}{|x| \sqrt{x^2 - 1}}[/itex], which http://en.wikipedia.org/wiki/Inverse_trigonometric_function" [Broken], but haven't yet found one which explains this detail for arccsc. Is there a proof that explains it?

Thanks,

- Farley

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# Proof of d/dx (arccsc x)

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