Proof of derivative uniqueness

In summary: Rudin provides a proof of uniqueness of a derivative. The inequality holds because it follows from the basic fact that, for any two numbers, u and v, |u- v|\le |u|+ |v|. To see this, Rudin uses the following two equations: u- v= A_2h- A_1h and u= f(x+ h)- f(x)- A_1h. He then uses the substitution u- v= Bh to solve for v, and the result is v= f(x+ h)- f(x)- A_2h. This means that |u- v|\le |u|+ |v|.
  • #1
NanoMath
11
0
Proof.png
Hello.
In the proof of uniqueness of ( multi-variable ) derivative from Rudin, I am a little stuck on why the inequality holds. Rest of the proof after that is clear .
 
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  • #2
Can you post a slightly larger image? That one is difficult for me to read.
 
  • #3
Proof.png
I'm sorry. Here you go.
 
  • #4
It follows from the basic fact that, for any two numbers, u and v, [itex]|u- v|\le |u|+ |v|[/itex].

Here, [itex]u= f(x+ h)- f(x)- A_1h[/itex] and [itex]v= f(x+ h)- f(x)- A_2h[/itex].

[itex]u- v= A_2h- A_1h= (A_2- A_1)h= Bh[/itex] so [itex]|u- v|= |Bh|[/itex]
Of course, |u|= |f(x+ h)- f(x)- A_1h| and |v|= |f(x+ h)- f(x)- A_2h| so that [itex]|u- v|\le |u|+ |v|[/itex] becomes
[itex]|Bh|\le |f(x+ h)- f(x)- A_1h|+ |f(x+ h)- f(x)- A_2h|[/itex]
 
  • #5
[tex]|B\mathbf{h}| = |A_2\mathbf{h} - A_1\mathbf{h}| = |\mathbf{f}(\mathbf{x} + \mathbf{h}) - \mathbf{f}(\mathbf{x}) - A_1\mathbf{h} - \mathbf{f}(\mathbf{x} + \mathbf{h}) +\mathbf{f}(\mathbf{x}) +A_2\mathbf{h}| \leq |\mathbf{f}(\mathbf{x} + \mathbf{h}) - \mathbf{f}(\mathbf{x}) - A_1\mathbf{h}| + |\mathbf{f}(\mathbf{x} + \mathbf{h}) -\mathbf{f}(\mathbf{x}) -A_2\mathbf{h}| [/tex]
 
  • #6
Utilize ##|b-a|\leq|b|+|a|## (Note equality holds when ##b## is positive and ##a## is negative or when ##a##is positive and ##b## is negative or when either of them or both of them are 0.) with ##a=|f(x+h)-f(x)-A_1h|## and ##b=|f(x+h)-f(x)-A_2h|##
EDIT:- dang, micromass beat me to it.
 
  • #7
Thanks a lot for answers.
 
  • #8
a function s is "little oh" if the limit of |s(x)|/|x| is zero as x-->0. then the derivative at a of a function f is a linear function L such that (f(a+x) -f(a) - L(x)) is little oh as a function of x. so just prove that the only little oh and linear function is zero. that does it by subtraction.

oh yes, and it is possible the reason you are confused is that you are reading the worst book in the world for understanding. For this particular topic I suggest you try (pages 138 and 142 of) Loomis and Sternberg: Advanced Calculus, (free on Sternberg's website).

Or Spivak, Calculus on manifolds, page 16, or Dieudonne': Foundations of modern analysis page 143, or Lang, Analysis I, pages 302-303. or Fleming: Functions of several variables (corollary of) Prop. 12, page 156.

Best to do the proof yourself as suggested above.
 
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1. What is "Proof of derivative uniqueness"?

"Proof of derivative uniqueness" is a mathematical concept that states that if a function has a derivative at a certain point, then that derivative is unique and cannot have any other value. This concept is important in calculus and is often used to prove mathematical theorems.

2. Why is "Proof of derivative uniqueness" important?

"Proof of derivative uniqueness" is important because it allows us to make precise mathematical statements and solve problems involving rates of change. It also helps us understand the behavior of functions and their derivatives, which is essential in many areas of science and engineering.

3. How is "Proof of derivative uniqueness" proven?

"Proof of derivative uniqueness" is proven using the Mean Value Theorem, which states that if a function is continuous on a closed interval and differentiable on the open interval, then there exists a point within the interval where the derivative of the function equals the slope of the secant line connecting the endpoints of the interval.

4. Can "Proof of derivative uniqueness" be applied to all functions?

Yes, "Proof of derivative uniqueness" can be applied to all continuous and differentiable functions. However, it may not be applicable to functions that are not continuous or differentiable at certain points.

5. What are some real-world applications of "Proof of derivative uniqueness"?

"Proof of derivative uniqueness" has many real-world applications, such as in physics and engineering where it is used to calculate rates of change and solve optimization problems. It is also used in economics to analyze supply and demand curves, and in biology to model population growth and decay.

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