if lim f(x)= infinity= lim g(x)(adsbygoogle = window.adsbygoogle || []).push({});

x->infinity x->infinty

and lim f'(x)/g'(x)=infinity

x-> infinity

then lim f(x)/g(x)=inifity

x-> inifinity

The above fact is what im trying to prove. From my notes, i see the following:

For m>0, choose k>0, such that if x> k* and g(x),f(x)>0,

then f'(x)/g'(x)> m(4/3).

this is actually where i get lost (so early into the process). can someone explain to me where exactly the prof is headed to with this info? also, is k a functional value through m? if so...how do i choose such k?

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# Proof of l'hopital 3

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