- #1
courtrigrad
- 1,236
- 2
Hello all
I need help with the following problems:
Prove that [tex] \lim_{x\rightarrow \infty} (\sqrt{n+1} - \sqrt n)(\sqrt {n+ \frac {1}{2}}) = \frac {1}{2} [/tex]
I know that [tex] \lim_{x\rightarrow \infty} (\sqrt{n+1} - \sqrt n) = 0 [/tex]. Then why wouldn't the limit be 0?
Also another question (I posted this in another thread, but it died :tongue2:)
[tex] a_n = \sqrt {n+1} - \sqrt n [/tex] find three numbers [tex] N_1 , N_2, N_3 [/tex] such that
[tex] a_n = \sqrt {n+1} - \sqrt n < \frac {1}{10} [/tex] for every [tex] n > N_1 [/tex]
[tex] a_n = \sqrt {n+1} - \sqrt n < \frac {1}{100} [/tex] for every [tex] n > N_2 [/tex]
[tex] a_n = \sqrt {n+1} - \sqrt n < \frac {1}{1000} [/tex] for every [tex] n > N_3 [/tex]
I need help with the following problems:
Prove that [tex] \lim_{x\rightarrow \infty} (\sqrt{n+1} - \sqrt n)(\sqrt {n+ \frac {1}{2}}) = \frac {1}{2} [/tex]
I know that [tex] \lim_{x\rightarrow \infty} (\sqrt{n+1} - \sqrt n) = 0 [/tex]. Then why wouldn't the limit be 0?
Also another question (I posted this in another thread, but it died :tongue2:)
[tex] a_n = \sqrt {n+1} - \sqrt n [/tex] find three numbers [tex] N_1 , N_2, N_3 [/tex] such that
[tex] a_n = \sqrt {n+1} - \sqrt n < \frac {1}{10} [/tex] for every [tex] n > N_1 [/tex]
[tex] a_n = \sqrt {n+1} - \sqrt n < \frac {1}{100} [/tex] for every [tex] n > N_2 [/tex]
[tex] a_n = \sqrt {n+1} - \sqrt n < \frac {1}{1000} [/tex] for every [tex] n > N_3 [/tex]