Let a>1. Prove the limit as n goes to [itex]\infty[/itex] of a1/n = 1.
The Attempt at a Solution
Given [itex]\epsilon[/itex] > 0, [itex]\forall[/itex]n>N, |a1/n-L|<[itex]\epsilon[/itex] and N=(a-1)/[itex]\epsilon[/itex].
|a1/n-L| = a1/n-1
...and that's where I get confused. I know that I have to multiply (a1/n-1) by something but I'm not sure what exactly (a hint my professor gave).