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Proof of Perfect Squares

  1. Jan 28, 2009 #1
    n=p1r1...pkrk

    In order for p to be a perfect square, r must be even. Therefore

    n=p12h1...pk2hk

    taking the square root of both sides i'm just left with

    n=p1h1...pkhk

    Does this work as a proof that n is a perfect square if r is even? It's a homework problem and I'm not sure if this is sufficient or correct at all.
     
  2. jcsd
  3. Jan 28, 2009 #2

    Dick

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    If the p's are distinct primes, it's true the r's must be even for n to be a perfect square, but you haven't proved it. You haven't even stated the problem coherently. What's p?
     
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