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Forums
Physics
Classical Physics
Electromagnetism
Proof of Q=CV for arbitrarily shaped capacitors
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[QUOTE="nasu, post: 6629442, member: 147320"] If you do see, consider a capacitor (or any conductor ) charged with a charge Q. The potential difference will have some value V. Now what if you have the same object charged with 2Q? You may say that the potential does not have to be 2V. But if you understand superposition, you can consider the charge 2Q as the superposition of Q and Q. We know that a charge Q on the capacitor produces a potential difference V so the effect of the two charges Q+Q will be V+V =2V. If this is not true then superposition is not true, is it? [/QUOTE]
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Forums
Physics
Classical Physics
Electromagnetism
Proof of Q=CV for arbitrarily shaped capacitors
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