Someone please help me show that (uv)^n= Summation {u^(i)v^(n-i)}(adsbygoogle = window.adsbygoogle || []).push({});

where i=0 the starting point and n is the ending number of the summation. By the way, there is also a term like (n) under the

(i)

summation which I wasn't sure how to account for. Since this is a more sophisticated version of induction which seems to account for two variables n and i, instead of just the usual n, I am a little stuck on how to approach this. Sorry for being a dumbass for the millionth time.

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# Proof of the formula for the nth derivative of a product

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