(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Recall that a function G(x) has the limit L as x tends to 1, written

lim as x -> infinity

G(x) = L,

if for any epsilon > 0, there exists M > 0 so that if x > M , then

|G(x) L| < epsilon.

This means that the limit of G(x) as x tends to 1 does not exist if for

any L and positive M, there exists epsilon > 0 so that for some x > M ,

|G(x) L| >= epsilon.

Using this deﬁnition, prove that

integral sinx dx from 2 pi to infinity diverges.

2. Relevant equations

3. The attempt at a solution

currently i just have no idea how to start this question up.

knowing that the integral is equals to -cos x + C, while cosine value is bouncing between -1 and 1, how do i start the proof using that definition

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# Proof that cos x diverges

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