let A,B be nonempty sets of real numbers, prove that:(adsbygoogle = window.adsbygoogle || []).push({});

if A,B are bounded and they are disjoint, then supA doesnt equal supB.

here's my proof:

assume that supA=supB=c

then for every a in A a<=c and for every b in B b<=c.

bacuse A.B are bounded then: for every e>0 there exists x in A such that

c-e<x<=c and there exists y in B such that c-e<y<=c so we have two elements that are both in A and B, but this is a contradiction.

is this proof valid?

i feel that i should show that y=x, but i think bacuse e is as we choose, we have to find elements which are both in A and B.

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# Proof with supremum.

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