# Proofs with Matricies

## The Attempt at a Solution

-(y, x) = -(YX-XY)
= XY-YX

Can I do this or would I have to define a matrix X= ( a b c d ) Y= ( e f g h)

And prove it that way? I am just really confused

Mark44
Mentor

## Homework Equations

View attachment 50857

## The Attempt at a Solution

-(y, x) = -(YX-XY)
= XY-YX

Can I do this or would I have to define a matrix X= ( a b c d ) Y= ( e f g h)

And prove it that way? I am just really confused

What you have above would work, but your notation is awful! Try to use the notation as given in the problem. Also notice that uppercase letters represent matrices, and lowercase letters represent the entries in a matrix.

Assuming that matrices X and Y are in M, then [X, Y] = ?
Keep working with the expressions you get until you end up with -[Y, X].

[X, Y]= YX- XY
Thus [Y, X]= XY- YX
then -[Y, X]= -(XY- YX)
then -[Y, X]= -XY +YX

Like that? So i don't have to use matricies with variables, just use X and Y to represent a matrix?

Mark44
Mentor
[X, Y]= YX- XY
Thus [Y, X]= XY- YX
then -[Y, X]= -(XY- YX)
then -[Y, X]= -XY +YX

Like that? So i don't have to use matricies with variables, just use X and Y to represent a matrix?

This is easier to follow.

[X, Y] = XY - YX = -(YX - XY) = -[Y, X]

Can you say why each pair of successive equal expressions is valid?

Properties of Matricies?

And Thanks your honestly a huge help!

Mark44
Mentor
Properties of Matricies?
That's pretty vague. Also, there are a number of steps. One reason doesn't fit them all.