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Properties of Roots of Real Numbers

  1. Jan 16, 2005 #1
    I have three problems that I can't seem to solve. I was wondering if anybody could help me or explain to me how to solve these. Note: * = multiplication.

    1. (6^1/2 * 2^1/3)^6

    2. ^4√7 + 2^4√1792

    3. 3(X-4)^1/2 + 5 = 11
     
  2. jcsd
  3. Jan 16, 2005 #2
    #2 seems to be missing a term. What is raised to 4 times square root of 7?

    #3 seems easy, I think. It reduces to: [tex]\sqrt{x-4}=2.[/tex]
    That gives x= 8, which works.

    For #1, use the binominal expansion: [tex](a+b)^6= a^6+6a^5b+15a^4b^2 +20a^3b^3+15a^2b^4+6ab^5+b^6.[/tex]
     
    Last edited: Jan 16, 2005
  4. Jan 17, 2005 #3

    HallsofIvy

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    1. (6^(1/2)*2^(1/3))^6

    That's "*", not "+", so you don't need the formula robert Ihnot gave:

    (6^(1/2)*2^(1/3))^6= (6^(1/2))^6*(2^(1/3))^6
    = 6^((1/2)*6)*2^((1/3)*6)= 6^3*2^2= 216*4= 864.
     
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