# Properties of Roots of Real Numbers

## Main Question or Discussion Point

I have three problems that I can't seem to solve. I was wondering if anybody could help me or explain to me how to solve these. Note: * = multiplication.

1. (6^1/2 * 2^1/3)^6

2. ^4√7 + 2^4√1792

3. 3(X-4)^1/2 + 5 = 11

#2 seems to be missing a term. What is raised to 4 times square root of 7?

#3 seems easy, I think. It reduces to: $$\sqrt{x-4}=2.$$
That gives x= 8, which works.

For #1, use the binominal expansion: $$(a+b)^6= a^6+6a^5b+15a^4b^2 +20a^3b^3+15a^2b^4+6ab^5+b^6.$$

Last edited:
HallsofIvy