(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

50uA beam of 1MeV proton

Target = Iron of 0.05um thick

Calculate scattered current density at distance 5 cm at 20 degrees angle

2. Relevant equations

[tex]\sigma(E,\theta)[/tex] = [tex]\pi*Z_{1}Z_{2}e^{4}(M_{1}/M_{2})/ET^{2}[/tex]

3. The attempt at a solution

I figured the probability of scattering to the angle is [tex]\frac{\int^{20}_{20}\sigma(E,\theta)d\Omega}{\int^{\pi}_{0}\sigma(E,\theta)d\Omega}[/tex]

Then how do i find the scattered current density with the info I have?

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# Homework Help: Proton scattering

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